How to override the login form in eZ5 ?
How to override the login form in eZ5 ?
Monday 18 March 2013 5:02:23 pm - 1 reply
Hi everyone !
I'm trying to use eZPublish 5 and I would like to override the login form and use a twig template and a symfony controller action instead if possible.
I was thinking of doing a simple form with a username and password in a new twig template and then create an action with the following code :
public function loginAction(Request $request)
{
$user = $request->request->get('username');
$password = $request->request->get('password');
$repository = $this->get('ezpublish.api.repository');
$userService = $repository->getUserService();
$user = $userService->loadUserByCredentials( $user, $password );$repository->setCurrentUser( $user );
return $this->render("MyBundle:index.html.twig"
}
But when I submit this login form, I'm not logged in, I'm still anonymous. What do I do wrong ? Thanks a lot!
Thursday 02 May 2013 3:51:29 pm
I guess, the problem is, you just loaded a eZ user object. This is necessary if you want to create, read etc. content with a specific user from the eZ 5 public API.
Loading a user object via loadUserByCredentials() does not create a security context within your Symfony application and therefore you are not logged.
I had a similar issue few days ago and only could workaround it, using the default way of logging in which is legacy module loading of /user/login at the moment (see src/EzSystems/DemoBundle/Resources/views/page_header_links.html.twig). This is a really bad practice and I really don't understand, why eZ would do this.
Maybe I missed something, but as far as I understood the sources, I'm only able to determine, if I'm logged in already e.g. via:
$securityContext = $this->container->get('security.context'); $currentlyLoggedInEzUser = $securityContext->getToken()->getUser()->getAPIUser();
If anybody has an idea of doing this the Symfony way, a notice in confluence or here is appreciated. Thanks! Hope this helps..
You must be logged in to post messages in this topic!
from
